Integrand size = 30, antiderivative size = 454 \[ \int \frac {(e x)^{7/2}}{\left (a-b x^2\right )^2 \left (c-d x^2\right )^{5/2}} \, dx=\frac {(2 b c+3 a d) e^3 \sqrt {e x}}{6 b (b c-a d)^2 \left (c-d x^2\right )^{3/2}}+\frac {a e^3 \sqrt {e x}}{2 b (b c-a d) \left (a-b x^2\right ) \left (c-d x^2\right )^{3/2}}+\frac {5 (b c+2 a d) e^3 \sqrt {e x}}{6 (b c-a d)^3 \sqrt {c-d x^2}}+\frac {5 \sqrt [4]{c} (b c+2 a d) e^{7/2} \sqrt {1-\frac {d x^2}{c}} \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right ),-1\right )}{6 \sqrt [4]{d} (b c-a d)^3 \sqrt {c-d x^2}}-\frac {5 \sqrt [4]{c} (b c+a d) e^{7/2} \sqrt {1-\frac {d x^2}{c}} \operatorname {EllipticPi}\left (-\frac {\sqrt {b} \sqrt {c}}{\sqrt {a} \sqrt {d}},\arcsin \left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right ),-1\right )}{4 \sqrt [4]{d} (b c-a d)^3 \sqrt {c-d x^2}}-\frac {5 \sqrt [4]{c} (b c+a d) e^{7/2} \sqrt {1-\frac {d x^2}{c}} \operatorname {EllipticPi}\left (\frac {\sqrt {b} \sqrt {c}}{\sqrt {a} \sqrt {d}},\arcsin \left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right ),-1\right )}{4 \sqrt [4]{d} (b c-a d)^3 \sqrt {c-d x^2}} \]
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Time = 0.64 (sec) , antiderivative size = 454, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.300, Rules used = {477, 481, 541, 537, 230, 227, 418, 1233, 1232} \[ \int \frac {(e x)^{7/2}}{\left (a-b x^2\right )^2 \left (c-d x^2\right )^{5/2}} \, dx=\frac {5 \sqrt [4]{c} e^{7/2} \sqrt {1-\frac {d x^2}{c}} (2 a d+b c) \operatorname {EllipticF}\left (\arcsin \left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right ),-1\right )}{6 \sqrt [4]{d} \sqrt {c-d x^2} (b c-a d)^3}-\frac {5 \sqrt [4]{c} e^{7/2} \sqrt {1-\frac {d x^2}{c}} (a d+b c) \operatorname {EllipticPi}\left (-\frac {\sqrt {b} \sqrt {c}}{\sqrt {a} \sqrt {d}},\arcsin \left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right ),-1\right )}{4 \sqrt [4]{d} \sqrt {c-d x^2} (b c-a d)^3}-\frac {5 \sqrt [4]{c} e^{7/2} \sqrt {1-\frac {d x^2}{c}} (a d+b c) \operatorname {EllipticPi}\left (\frac {\sqrt {b} \sqrt {c}}{\sqrt {a} \sqrt {d}},\arcsin \left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right ),-1\right )}{4 \sqrt [4]{d} \sqrt {c-d x^2} (b c-a d)^3}+\frac {5 e^3 \sqrt {e x} (2 a d+b c)}{6 \sqrt {c-d x^2} (b c-a d)^3}+\frac {e^3 \sqrt {e x} (3 a d+2 b c)}{6 b \left (c-d x^2\right )^{3/2} (b c-a d)^2}+\frac {a e^3 \sqrt {e x}}{2 b \left (a-b x^2\right ) \left (c-d x^2\right )^{3/2} (b c-a d)} \]
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Rule 227
Rule 230
Rule 418
Rule 477
Rule 481
Rule 537
Rule 541
Rule 1232
Rule 1233
Rubi steps \begin{align*} \text {integral}& = \frac {2 \text {Subst}\left (\int \frac {x^8}{\left (a-\frac {b x^4}{e^2}\right )^2 \left (c-\frac {d x^4}{e^2}\right )^{5/2}} \, dx,x,\sqrt {e x}\right )}{e} \\ & = \frac {a e^3 \sqrt {e x}}{2 b (b c-a d) \left (a-b x^2\right ) \left (c-d x^2\right )^{3/2}}-\frac {e^3 \text {Subst}\left (\int \frac {a c+\frac {(4 b c+5 a d) x^4}{e^2}}{\left (a-\frac {b x^4}{e^2}\right ) \left (c-\frac {d x^4}{e^2}\right )^{5/2}} \, dx,x,\sqrt {e x}\right )}{2 b (b c-a d)} \\ & = \frac {(2 b c+3 a d) e^3 \sqrt {e x}}{6 b (b c-a d)^2 \left (c-d x^2\right )^{3/2}}+\frac {a e^3 \sqrt {e x}}{2 b (b c-a d) \left (a-b x^2\right ) \left (c-d x^2\right )^{3/2}}+\frac {e^5 \text {Subst}\left (\int \frac {-\frac {10 a b c^2}{e^2}-\frac {10 b c (2 b c+3 a d) x^4}{e^4}}{\left (a-\frac {b x^4}{e^2}\right ) \left (c-\frac {d x^4}{e^2}\right )^{3/2}} \, dx,x,\sqrt {e x}\right )}{12 b c (b c-a d)^2} \\ & = \frac {(2 b c+3 a d) e^3 \sqrt {e x}}{6 b (b c-a d)^2 \left (c-d x^2\right )^{3/2}}+\frac {a e^3 \sqrt {e x}}{2 b (b c-a d) \left (a-b x^2\right ) \left (c-d x^2\right )^{3/2}}+\frac {5 (b c+2 a d) e^3 \sqrt {e x}}{6 (b c-a d)^3 \sqrt {c-d x^2}}-\frac {e^7 \text {Subst}\left (\int \frac {\frac {20 a b c^2 (2 b c+a d)}{e^4}+\frac {20 b^2 c^2 (b c+2 a d) x^4}{e^6}}{\left (a-\frac {b x^4}{e^2}\right ) \sqrt {c-\frac {d x^4}{e^2}}} \, dx,x,\sqrt {e x}\right )}{24 b c^2 (b c-a d)^3} \\ & = \frac {(2 b c+3 a d) e^3 \sqrt {e x}}{6 b (b c-a d)^2 \left (c-d x^2\right )^{3/2}}+\frac {a e^3 \sqrt {e x}}{2 b (b c-a d) \left (a-b x^2\right ) \left (c-d x^2\right )^{3/2}}+\frac {5 (b c+2 a d) e^3 \sqrt {e x}}{6 (b c-a d)^3 \sqrt {c-d x^2}}-\frac {\left (5 a (b c+a d) e^3\right ) \text {Subst}\left (\int \frac {1}{\left (a-\frac {b x^4}{e^2}\right ) \sqrt {c-\frac {d x^4}{e^2}}} \, dx,x,\sqrt {e x}\right )}{2 (b c-a d)^3}+\frac {\left (5 (b c+2 a d) e^3\right ) \text {Subst}\left (\int \frac {1}{\sqrt {c-\frac {d x^4}{e^2}}} \, dx,x,\sqrt {e x}\right )}{6 (b c-a d)^3} \\ & = \frac {(2 b c+3 a d) e^3 \sqrt {e x}}{6 b (b c-a d)^2 \left (c-d x^2\right )^{3/2}}+\frac {a e^3 \sqrt {e x}}{2 b (b c-a d) \left (a-b x^2\right ) \left (c-d x^2\right )^{3/2}}+\frac {5 (b c+2 a d) e^3 \sqrt {e x}}{6 (b c-a d)^3 \sqrt {c-d x^2}}-\frac {\left (5 (b c+a d) e^3\right ) \text {Subst}\left (\int \frac {1}{\left (1-\frac {\sqrt {b} x^2}{\sqrt {a} e}\right ) \sqrt {c-\frac {d x^4}{e^2}}} \, dx,x,\sqrt {e x}\right )}{4 (b c-a d)^3}-\frac {\left (5 (b c+a d) e^3\right ) \text {Subst}\left (\int \frac {1}{\left (1+\frac {\sqrt {b} x^2}{\sqrt {a} e}\right ) \sqrt {c-\frac {d x^4}{e^2}}} \, dx,x,\sqrt {e x}\right )}{4 (b c-a d)^3}+\frac {\left (5 (b c+2 a d) e^3 \sqrt {1-\frac {d x^2}{c}}\right ) \text {Subst}\left (\int \frac {1}{\sqrt {1-\frac {d x^4}{c e^2}}} \, dx,x,\sqrt {e x}\right )}{6 (b c-a d)^3 \sqrt {c-d x^2}} \\ & = \frac {(2 b c+3 a d) e^3 \sqrt {e x}}{6 b (b c-a d)^2 \left (c-d x^2\right )^{3/2}}+\frac {a e^3 \sqrt {e x}}{2 b (b c-a d) \left (a-b x^2\right ) \left (c-d x^2\right )^{3/2}}+\frac {5 (b c+2 a d) e^3 \sqrt {e x}}{6 (b c-a d)^3 \sqrt {c-d x^2}}+\frac {5 \sqrt [4]{c} (b c+2 a d) e^{7/2} \sqrt {1-\frac {d x^2}{c}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right )\right |-1\right )}{6 \sqrt [4]{d} (b c-a d)^3 \sqrt {c-d x^2}}-\frac {\left (5 (b c+a d) e^3 \sqrt {1-\frac {d x^2}{c}}\right ) \text {Subst}\left (\int \frac {1}{\left (1-\frac {\sqrt {b} x^2}{\sqrt {a} e}\right ) \sqrt {1-\frac {d x^4}{c e^2}}} \, dx,x,\sqrt {e x}\right )}{4 (b c-a d)^3 \sqrt {c-d x^2}}-\frac {\left (5 (b c+a d) e^3 \sqrt {1-\frac {d x^2}{c}}\right ) \text {Subst}\left (\int \frac {1}{\left (1+\frac {\sqrt {b} x^2}{\sqrt {a} e}\right ) \sqrt {1-\frac {d x^4}{c e^2}}} \, dx,x,\sqrt {e x}\right )}{4 (b c-a d)^3 \sqrt {c-d x^2}} \\ & = \frac {(2 b c+3 a d) e^3 \sqrt {e x}}{6 b (b c-a d)^2 \left (c-d x^2\right )^{3/2}}+\frac {a e^3 \sqrt {e x}}{2 b (b c-a d) \left (a-b x^2\right ) \left (c-d x^2\right )^{3/2}}+\frac {5 (b c+2 a d) e^3 \sqrt {e x}}{6 (b c-a d)^3 \sqrt {c-d x^2}}+\frac {5 \sqrt [4]{c} (b c+2 a d) e^{7/2} \sqrt {1-\frac {d x^2}{c}} F\left (\left .\sin ^{-1}\left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right )\right |-1\right )}{6 \sqrt [4]{d} (b c-a d)^3 \sqrt {c-d x^2}}-\frac {5 \sqrt [4]{c} (b c+a d) e^{7/2} \sqrt {1-\frac {d x^2}{c}} \Pi \left (-\frac {\sqrt {b} \sqrt {c}}{\sqrt {a} \sqrt {d}};\left .\sin ^{-1}\left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right )\right |-1\right )}{4 \sqrt [4]{d} (b c-a d)^3 \sqrt {c-d x^2}}-\frac {5 \sqrt [4]{c} (b c+a d) e^{7/2} \sqrt {1-\frac {d x^2}{c}} \Pi \left (\frac {\sqrt {b} \sqrt {c}}{\sqrt {a} \sqrt {d}};\left .\sin ^{-1}\left (\frac {\sqrt [4]{d} \sqrt {e x}}{\sqrt [4]{c} \sqrt {e}}\right )\right |-1\right )}{4 \sqrt [4]{d} (b c-a d)^3 \sqrt {c-d x^2}} \\ \end{align*}
Result contains higher order function than in optimal. Order 6 vs. order 4 in optimal.
Time = 11.30 (sec) , antiderivative size = 252, normalized size of antiderivative = 0.56 \[ \int \frac {(e x)^{7/2}}{\left (a-b x^2\right )^2 \left (c-d x^2\right )^{5/2}} \, dx=\frac {e^3 \sqrt {e x} \left (a \left (b^2 c x^2 \left (7 c-5 d x^2\right )+a^2 d \left (-5 c+7 d x^2\right )-2 a b \left (5 c^2-8 c d x^2+5 d^2 x^4\right )\right )+5 a (2 b c+a d) \left (a-b x^2\right ) \left (c-d x^2\right ) \sqrt {1-\frac {d x^2}{c}} \operatorname {AppellF1}\left (\frac {1}{4},\frac {1}{2},1,\frac {5}{4},\frac {d x^2}{c},\frac {b x^2}{a}\right )+b (b c+2 a d) x^2 \left (a-b x^2\right ) \left (c-d x^2\right ) \sqrt {1-\frac {d x^2}{c}} \operatorname {AppellF1}\left (\frac {5}{4},\frac {1}{2},1,\frac {9}{4},\frac {d x^2}{c},\frac {b x^2}{a}\right )\right )}{6 a (b c-a d)^3 \left (-a+b x^2\right ) \left (c-d x^2\right )^{3/2}} \]
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Leaf count of result is larger than twice the leaf count of optimal. \(1192\) vs. \(2(360)=720\).
Time = 2.91 (sec) , antiderivative size = 1193, normalized size of antiderivative = 2.63
method | result | size |
elliptic | \(\text {Expression too large to display}\) | \(1193\) |
default | \(\text {Expression too large to display}\) | \(4391\) |
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Timed out. \[ \int \frac {(e x)^{7/2}}{\left (a-b x^2\right )^2 \left (c-d x^2\right )^{5/2}} \, dx=\text {Timed out} \]
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Timed out. \[ \int \frac {(e x)^{7/2}}{\left (a-b x^2\right )^2 \left (c-d x^2\right )^{5/2}} \, dx=\text {Timed out} \]
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\[ \int \frac {(e x)^{7/2}}{\left (a-b x^2\right )^2 \left (c-d x^2\right )^{5/2}} \, dx=\int { \frac {\left (e x\right )^{\frac {7}{2}}}{{\left (b x^{2} - a\right )}^{2} {\left (-d x^{2} + c\right )}^{\frac {5}{2}}} \,d x } \]
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\[ \int \frac {(e x)^{7/2}}{\left (a-b x^2\right )^2 \left (c-d x^2\right )^{5/2}} \, dx=\int { \frac {\left (e x\right )^{\frac {7}{2}}}{{\left (b x^{2} - a\right )}^{2} {\left (-d x^{2} + c\right )}^{\frac {5}{2}}} \,d x } \]
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Timed out. \[ \int \frac {(e x)^{7/2}}{\left (a-b x^2\right )^2 \left (c-d x^2\right )^{5/2}} \, dx=\int \frac {{\left (e\,x\right )}^{7/2}}{{\left (a-b\,x^2\right )}^2\,{\left (c-d\,x^2\right )}^{5/2}} \,d x \]
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